35, 76, 253, 488, 911, ? | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The pattern follows the logic: $(5n) 	imes (n+1)^2 \pm (15 - n + 1)$ where $n$ starts from $1$.For $n=1$: $5 	imes 2^2 + 15 = 35$For $n=2$: $10

Vedclass · Accepted Answer

$1460$

Vedclass · Answer

(C) The pattern follows the logic: $(5n) 	imes (n+1)^2 \pm (15 - n + 1)$ where $n$ starts from $1$.For $n=1$: $5 	imes 2^2 + 15 = 35$For $n=2$: $10 	imes 3^2 - 14 = 76$For $n=3$: $15 	imes 4^2 + 13 = 253$For $n=4$: $20 	imes 5^2 - 12 = 488$For $n=5$: $25 	imes 6^2 + 11 = 911$For $n=6$: $30 	imes 7^2 - 10 = 1460$Thus,the next term in the series is $1460$.

$600$	$360$	$360$	$450$	$600$	$800$
$1200$	$(A)$	$(B)$	$(C)$	$(D)$	$(E)$

$1260$	$628$	$312$	$154$
$788$	$(a)$	$(b)$	$(c)$	$(d)$	$(e)$

$35, 76, 253, 488, 911, ?$

Similar Questions

$4, 9, 25, ?, 121, 169, 289, 361$

$600$ $360$ $360$ $450$ $600$ $800$
$1200$ $(A)$ $(B)$ $(C)$ $(D)$ $(E)$

What should come in place of $B$?

Observe the following table and determine which number will come in place of $(d)$:
$1260$ $628$ $312$ $154$
$788$ $(a)$ $(b)$ $(c)$ $(d)$ $(e)$

$4, 10, 33, 136, \dots$

Find the odd man out:
$4096, 3072, 2048, 1728, 1296$

Vedclass Test Series

Exam Paper Generator

Online Exam Module