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(D) Given that $A$ and $B$ are independent events,the probability of neither $A$ nor $B$ occurring is given by $P(\bar{A} \cap \bar{B})$.Since $A$ and

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$1/3$

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(D) Given that $A$ and $B$ are independent events,the probability of neither $A$ nor $B$ occurring is given by $P(\bar{A} \cap \bar{B})$.Since $A$ and $B$ are independent,their complements $\bar{A}$ and $\bar{B}$ are also independent.Therefore,$P(\bar{A} \cap \bar{B}) = P(\bar{A}) 	imes P(\bar{B})$.We know that $P(\bar{A}) = 1 - P(A) = 1 - 1/2 = 1/2$.Similarly,$P(\bar{B}) = 1 - P(B) = 1 - 1/3 = 2/3$.Thus,$P(\bar{A} \cap \bar{B}) = (1/2) 	imes (2/3) = 1/3$.

$A$ and $B$ are two independent events such that $P(A) = 1/2$ and $P(B) = 1/3$. Then $P$ (neither $A$ nor $B$) is equal to

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