$But-1-yne$ reacts with cold alkaline $KMnO_4$ to produce:

Consider the following transformations of a compound $P$ $(C_9H_{12})$:
$(i)$ $P \xrightarrow{NaNH_2, C_6H_5COCH_3, H_3O^+/\Delta} R$ (Optically active)
(ii) $P \xrightarrow{Pt/H_2} \text{propylcyclohexane}$
(iii) $P \xrightarrow{X, KMnO_4/H_2SO_4/\Delta} Q$ ($C_8H_{12}O_6$,Optically active acid)
Choose the correct option$(s)$:
$(A)$ $P$ is $3-$cyclohexylprop$-1-$yne
$(B)$ $X$ is $Pd-C/\text{quinoline}/H_2$
$(C)$ $P$ is $1-$cyclohexylprop$-2-$yne
$(D)$ $R$ is $1-$cyclohexyl$-4-$phenylbut$-3-$yn$-2-$ol

In the given reactions,find the sum of $(x + y)$.
$(1)$ $Ph-C(Br)_2-CH_3$ $\xrightarrow{xNaNH_2} (A)$ $\xrightarrow{CH_3I} Ph-C \equiv C-CH_3$
$(2)$ $CH_3-CH_2-C(Br)_2-CH_3 \xrightarrow{yNaNH_2} CH_3-C \equiv C-CH_3$
Find the value of $(x + y)$.

The major product of the following reaction is $P$. Number of oxygen atoms present in product $P$ is $. . . . . . . . . . . (nearest integer)$.

An inorganic metal oxide $(A)$ heated with carbon gives compound $(B)$,which on reaction with water gives ethyne. What are the compounds $(A)$ and $(B)$?

The triple bond of ethyne is made of,or the cylindrical shape of an alkyne is due to: