12 frac{5}{7} + 23 frac{3}{5} - 14 frac{1}{3} | vedclass

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Question

(C) Let the missing value be $x$.$12 \frac{5}{7} + 23 \frac{3}{5} - 14 \frac{1}{3} = 28 \frac{4}{7} - x$$x = 28 \frac{4}{7} + 14 \frac{1}{3} - 23 \fra

Vedclass · Accepted Answer

$6 \frac{62}{105}$

Vedclass · Answer

(C) Let the missing value be $x$.$12 \frac{5}{7} + 23 \frac{3}{5} - 14 \frac{1}{3} = 28 \frac{4}{7} - x$$x = 28 \frac{4}{7} + 14 \frac{1}{3} - 23 \frac{3}{5} - 12 \frac{5}{7}$Group the whole numbers and fractions:$x = (28 + 14 - 23 - 12) + (\frac{4}{7} + \frac{1}{3} - \frac{3}{5} - \frac{5}{7})$$x = 7 + (\frac{4}{7} - \frac{5}{7} + \frac{1}{3} - \frac{3}{5})$$x = 7 + (-\frac{1}{7} + \frac{5 - 9}{15})$$x = 7 - \frac{1}{7} - \frac{4}{15}$Find a common denominator for the fractions $(105)$:$x = 7 - (\frac{15 + 28}{105})$$x = 7 - \frac{43}{105}$$x = 6 + (1 - \frac{43}{105}) = 6 + \frac{62}{105} = 6 \frac{62}{105}$

$12 \frac{5}{7} + 23 \frac{3}{5} - 14 \frac{1}{3} = 28 \frac{4}{7} - ?$

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