22 frac{2}{9} + 33 frac{4}{7} - ? = 28 frac{4 | vedclass

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(C) Given equation: $22 \frac{2}{9} + 33 \frac{4}{7} - ? = 28 \frac{4}{45}$Rearranging for $?$: $? = 22 \frac{2}{9} + 33 \frac{4}{7} - 28 \frac{4}{45}

Vedclass · Accepted Answer

$27 \frac{74}{105}$

Vedclass · Answer

(C) Given equation: $22 \frac{2}{9} + 33 \frac{4}{7} - ? = 28 \frac{4}{45}$Rearranging for $?$: $? = 22 \frac{2}{9} + 33 \frac{4}{7} - 28 \frac{4}{45}$Separate the whole numbers and fractions: $? = (22 + 33 - 28) + (\frac{2}{9} + \frac{4}{7} - \frac{4}{45})$Calculate the whole number part: $22 + 33 - 28 = 27$Find the common denominator for the fractions $(9, 7, 45)$: The Least Common Multiple $(LCM)$ of $9, 7, 45$ is $315$.Convert fractions: $\frac{2}{9} = \frac{2 	imes 35}{315} = \frac{70}{315}$,$\frac{4}{7} = \frac{4 	imes 45}{315} = \frac{180}{315}$,$\frac{4}{45} = \frac{4 	imes 7}{315} = \frac{28}{315}$Combine fractions: $\frac{70 + 180 - 28}{315} = \frac{222}{315}$Simplify the fraction: $\frac{222 \div 3}{315 \div 3} = \frac{74}{105}$Result: $27 + \frac{74}{105} = 27 \frac{74}{105}$

$22 \frac{2}{9} + 33 \frac{4}{7} - ? = 28 \frac{4}{45}$

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