$7 \frac{11}{18} + 13 \frac{1}{9} + 5 \frac{7}{9} - 16 \frac{2}{3} = ?$

  • A
    $9 \frac{5}{6}$
  • B
    $9 \frac{5}{18}$
  • C
    $9 \frac{1}{6}$
  • D
    $8 \frac{5}{6}$

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If we multiply a fraction by itself and divide the product by its reciprocal,the fraction thus obtained is $18 \frac{26}{27}$. The fraction is

$\frac{\frac{1}{3}+\frac{1}{3} \times \frac{1}{3}}{\frac{1}{3}+\frac{1}{3} \text{ of } \frac{1}{3}}-\frac{1}{9} = ?$

The unit's digit of the number $6^{256} - 4^{256}$ is

$\frac{0.0203 \times 2.92}{0.0073 \times 14.5 \times 0.7} = ?$

Simplified form of $\left[\left(\sqrt[5]{x^{-3 / 5}}\right)^{-5 / 3}\right]^{5}$ is

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