3 . overline{87} - 2 . overline{59} = ? | vedclass

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Question

(D) To solve $3 . \overline{87} - 2 . \overline{59}$,we convert the recurring decimals into fractions.$3 . \overline{87} = 3 + \frac{87}{99} = \frac{3

Vedclass · Accepted Answer

$1 . \overline{28}$

Vedclass · Answer

(D) To solve $3 . \overline{87} - 2 . \overline{59}$,we convert the recurring decimals into fractions.$3 . \overline{87} = 3 + \frac{87}{99} = \frac{3 	imes 99 + 87}{99} = \frac{297 + 87}{99} = \frac{384}{99}$.$2 . \overline{59} = 2 + \frac{59}{99} = \frac{2 	imes 99 + 59}{99} = \frac{198 + 59}{99} = \frac{257}{99}$.Now,subtract the two fractions:$\frac{384}{99} - \frac{257}{99} = \frac{384 - 257}{99} = \frac{127}{99}$.Converting $\frac{127}{99}$ back to a recurring decimal:$\frac{127}{99} = 1 + \frac{28}{99} = 1 . \overline{28}$.

$3 . \overline{87} - 2 . \overline{59} = ?$

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