3 coins are tossed. Find the probability of g | vedclass

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(A) When $3$ coins are tossed,the sample space $S$ is given by:$S = \{HHH, HHT, HTH, THH, HTT, THT, TTH, TTT\}$Total number of exhaustive cases $= 8$.

Vedclass · Accepted Answer

$\frac{1}{2}$

Vedclass · Answer

(A) When $3$ coins are tossed,the sample space $S$ is given by:$S = \{HHH, HHT, HTH, THH, HTT, THT, TTH, TTT\}$Total number of exhaustive cases $= 8$.We need to find the probability of getting at least $2$ heads. The favorable outcomes are:$E = \{HHH, HHT, HTH, THH\}$Number of favorable cases $= 4$.Therefore,the probability $P$ is:$P(	ext{at least } 2 	ext{ heads}) = \frac{	ext{Number of favorable cases}}{	ext{Total number of cases}} = \frac{4}{8} = \frac{1}{2}$.

$3$ coins are tossed. Find the probability of getting at least $2$ heads.

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