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(C) When $2$ dice are thrown,the total number of possible outcomes is $n(S) = 6 	imes 6 = 36$.$A$ doublet of even numbers means both dice show the sa

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$\frac{1}{12}$

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(C) When $2$ dice are thrown,the total number of possible outcomes is $n(S) = 6 	imes 6 = 36$.$A$ doublet of even numbers means both dice show the same even number.The possible outcomes for this event $A$ are: $A = \{(2, 2), (4, 4), (6, 6)\}$.The number of favorable outcomes is $n(A) = 3$.The probability $P(A)$ is given by the formula: $P(A) = \frac{n(A)}{n(S)}$.Substituting the values: $P(A) = \frac{3}{36} = \frac{1}{12}$.

$2$ dice are thrown. Find the probability of getting a doublet of even numbers.

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