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(C) When $2$ dice are thrown,the total number of possible outcomes is $6 	imes 6 = 36$.Let $A$ be the event of getting a sum of $6$.The favorable out

Vedclass · Accepted Answer

$31:5$

Vedclass · Answer

(C) When $2$ dice are thrown,the total number of possible outcomes is $6 	imes 6 = 36$.Let $A$ be the event of getting a sum of $6$.The favorable outcomes for event $A$ are: $(1, 5), (5, 1), (2, 4), (4, 2), (3, 3)$.Thus,the number of favorable outcomes $n(A) = 5$.The number of unfavorable outcomes is the total outcomes minus the favorable outcomes: $36 - 5 = 31$.The odds against an event are defined as the ratio of unfavorable outcomes to favorable outcomes.Therefore,the odds against getting the sum $6$ are $31:5$.

$2$ dice are thrown. Find the odds against getting the sum $6$.

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