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(B) $1$. The cross is between $AABB$ (homozygous dominant) and $aabb$ (homozygous recessive).$2$. The offspring produced from this cross will have the

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$4$

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(B) $1$. The cross is between $AABB$ (homozygous dominant) and $aabb$ (homozygous recessive).$2$. The offspring produced from this cross will have the genotype $AaBb$.$3$. The number of types of gametes produced by an organism with genotype $AaBb$ is calculated using the formula $2^n$,where $n$ is the number of heterozygous gene pairs.$4$. Here,$n = 2$ (since $Aa$ and $Bb$ are heterozygous).$5$. Therefore,the number of types of gametes = $2^2 = 4$.

How many types of gametes will be produced by the offspring resulting from the cross $AABB \times aabb$?

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