If a DNA fragment contains A = 166 and C = 14 | vedclass

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(C) According to $Chargaff's$ rule,in a double-stranded $DNA$ molecule,the amount of Adenine $(A)$ is equal to Thymine $(T)$,and the amount of Cytosin

Vedclass · Accepted Answer

$310$

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(C) According to $Chargaff's$ rule,in a double-stranded $DNA$ molecule,the amount of Adenine $(A)$ is equal to Thymine $(T)$,and the amount of Cytosine $(C)$ is equal to Guanine $(G)$.Given: $A = 166$ and $C = 144$.Therefore,$T = A = 166$ and $G = C = 144$.The total number of nitrogenous bases is the sum of all four bases: $A + T + G + C = 166 + 166 + 144 + 144 = 620$.The number of base pairs is half the total number of bases: $620 / 2 = 310$.

If a $DNA$ fragment contains $A = 166$ and $C = 144$,what is the total number of nitrogenous base pairs in that fragment?

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