If the genetic code is a triplet,how many cod | vedclass

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(D) The genetic code is based on $4$ nitrogenous bases: Adenine $(A)$,Guanine $(G)$,Cytosine $(C)$,and Uracil $(U)$.Since the genetic code is a triple

Vedclass · Accepted Answer

$64$

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(D) The genetic code is based on $4$ nitrogenous bases: Adenine $(A)$,Guanine $(G)$,Cytosine $(C)$,and Uracil $(U)$.Since the genetic code is a triplet,each codon consists of $3$ nitrogenous bases.The total number of possible codons is calculated by the formula $4^n$,where $n$ is the number of bases per codon.Here,$n = 3$,so the total number of codons = $4^3 = 4 	imes 4 	imes 4 = 64$.

Column-$I$	Column-$II$
$A$. $AUG$	$1$. Phenylalanine
$B$. $UAA$	$2$. Methionine
$C$. $UUU$	$3$. Tryptophan
$D$. $UGG$	$4$. Stop

If the genetic code is a triplet,how many codons will be formed?

Similar Questions

Out of $64$ codons,$61$ codons code for $20$ different amino acids. What is this property of the genetic code called?

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Choose the correct pair.

Column-$I$ Column-$II$

$A$. $AUG$ $1$. Phenylalanine

$B$. $UAA$ $2$. Methionine

$C$. $UUU$ $3$. Tryptophan

$D$. $UGG$ $4$. Stop

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