If 51% of the members in a population possess | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to the Hardy-Weinberg principle,the sum of allele frequencies is $p + q = 1$,where $p$ is the frequency of the dominant allele and $q$ i

Vedclass · Accepted Answer

$0.91$

Vedclass · Answer

(C) According to the Hardy-Weinberg principle,the sum of allele frequencies is $p + q = 1$,where $p$ is the frequency of the dominant allele and $q$ is the frequency of the recessive allele.Individuals with at least one recessive allele include both homozygous recessive $(q^2)$ and heterozygous $(2pq)$ genotypes.The frequency of individuals with at least one recessive allele is given by $q^2 + 2pq = 0.51$.Since $p^2 + 2pq + q^2 = 1$,we can write $p^2 = 1 - (q^2 + 2pq)$.Substituting the given value: $p^2 = 1 - 0.51 = 0.49$.The frequency of the dominant phenotype is represented by $p^2$ (homozygous dominant) plus $2pq$ (heterozygous),which is $1 - q^2$. However,the question asks for the frequency of the dominant phenotype,which is $p^2 + 2pq = 1 - q^2$. Wait,the dominant phenotype is $p^2 + 2pq$. Since $p^2 + 2pq + q^2 = 1$,the dominant phenotype frequency is $1 - q^2$. Actually,the frequency of the recessive phenotype is $q^2$. Given $q^2 + 2pq = 0.51$,we know $p^2 = 1 - (q^2 + 2pq) = 1 - 0.51 = 0.49$. Since $p^2 = 0.49$,$p = 0.7$. Then $q = 1 - 0.7 = 0.3$.The dominant phenotype frequency is $p^2 + 2pq = (0.7)^2 + 2(0.7)(0.3) = 0.49 + 0.42 = 0.91$.

If $51\%$ of the members in a population possess at least one recessive allele,find the frequency of the dominant phenotype.

Similar Questions

In a population that is in Hardy-Weinberg equilibrium,the frequency of the recessive allele for a certain genetic trait is $0.20$. What percentage of individuals in the next generation is expected to show the dominant trait (in $\%$)?

In a population of $1000$ individuals, $360$ belong to genotype $AA$, $480$ to $Aa$, and the remaining $160$ to $aa$. Based on this data, the frequency of allele $A$ in the population is:

In a population,$36 \%$ of individuals exhibit the recessive trait. The frequency of the dominant allele in this population is ......

$A$ population will not exist in Hardy-Weinberg equilibrium if

In the Hardy-Weinberg equation,the frequency of heterozygous individuals is represented by:

Vedclass Test Series

Exam Paper Generator

Online Exam Module