$80$ bulbs are selected at random from a lot and their lifetime (in $hrs$) is recorded in the form of a frequency table given below:
Lifetime (in hours) $300$ $500$ $700$ $900$ $1100$ Frequency $10$ $12$ $23$ $25$ $10$
The probability that a bulb selected randomly from the lot has a lifetime less than $900$ hours is:
| Lifetime (in hours) | $300$ | $500$ | $700$ | $900$ | $1100$ |
| Frequency | $10$ | $12$ | $23$ | $25$ | $10$ |
The probability that a bulb selected randomly from the lot has a lifetime less than $900$ hours is:
- A$\frac{11}{40}$
- B$\frac{5}{16}$
- C$\frac{9}{16}$
- D$\frac{7}{16}$
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$A$ bag contains $40$ balls of the same shape and weight. Among the balls, $18$ are red, $12$ are yellow, and the rest are blue. What is the probability that a ball drawn at random from the bag is blue?
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View Solution$80$ bulbs are selected at random from a lot and their lifetime (in $hrs$) is recorded in the form of a frequency table given below:
Lifetime (in hours) $300$ $500$ $700$ $900$ $1100$ Frequency $10$ $12$ $23$ $25$ $10$
One bulb is selected at random from the lot. The probability that its lifetime is $1150$ hours is:
| Lifetime (in hours) | $300$ | $500$ | $700$ | $900$ | $1100$ |
| Frequency | $10$ | $12$ | $23$ | $25$ | $10$ |
One bulb is selected at random from the lot. The probability that its lifetime is $1150$ hours is:
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Monthly income (in Rs) $0$ Televisions $1$ Television $2$ Televisions Above $2$ Televisions $< 10000$ $20$ $80$ $10$ $0$ $10000-14999$ $10$ $240$ $60$ $0$ $15000-19999$ $0$ $380$ $120$ $30$ $20000-24999$ $0$ $520$ $370$ $80$ $25000$ and above $0$ $1100$ $760$ $220$
Find the probability of a household earning $Rs. 25000$ and more per month and owning $2$ televisions.
| Monthly income (in Rs) | $0$ Televisions | $1$ Television | $2$ Televisions | Above $2$ Televisions |
| $< 10000$ | $20$ | $80$ | $10$ | $0$ |
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| $15000-19999$ | $0$ | $380$ | $120$ | $30$ |
| $20000-24999$ | $0$ | $520$ | $370$ | $80$ |
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Find the probability of a household earning $Rs. 25000$ and more per month and owning $2$ televisions.
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Number of girls in a family $0$ $1$ $2$ Number of families $128$ $672$ $200$
Compute the probability of a family,chosen at random,having $(1)$ two girls,$(2)$ one girl.
| Number of girls in a family | $0$ | $1$ | $2$ |
| Number of families | $128$ | $672$ | $200$ |
Compute the probability of a family,chosen at random,having $(1)$ two girls,$(2)$ one girl.
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View SolutionIn an oratory competition,$30$ students participated,out of which $12$ are boys. Find the probability that the first prize is won by a girl.
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