sin (90^circ - theta) = ldots ldots ldots | vedclass

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(A) In trigonometry,the trigonometric ratios of complementary angles are defined as follows:$\sin (90^\circ - 	heta) = \cos 	heta$$\cos (90^\circ -

Vedclass · Accepted Answer

$\cos 	heta$

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(A) In trigonometry,the trigonometric ratios of complementary angles are defined as follows:$\sin (90^\circ - 	heta) = \cos 	heta$$\cos (90^\circ - 	heta) = \sin 	heta$$	an (90^\circ - 	heta) = \cot 	heta$$\cot (90^\circ - 	heta) = 	an 	heta$$\sec (90^\circ - 	heta) = \operatorname{cosec} 	heta$$\operatorname{cosec} (90^\circ - 	heta) = \sec 	heta$Therefore,based on the standard trigonometric identity for complementary angles,$\sin (90^\circ - 	heta) = \cos 	heta$.

$\sin (90^\circ - \theta) = \ldots \ldots \ldots$

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Write 'True' or 'False' and justify your answer.
The value of $2 \sin \theta$ can be $(a + \frac{1}{a}),$ where $a$ is a positive number,and $a \neq 1$.

For acute angle $\theta,$ if $\cos \theta = \sin \theta,$ then $2 \tan^{2} \theta + \sin^{2} \theta + 1 = \ldots$

Write 'True' or 'False' and justify your answer.
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