tan (90^circ - theta) = ldots ldots ldots | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In trigonometry,the trigonometric ratios of complementary angles are defined as follows:$\sin (90^\circ - 	heta) = \cos 	heta$$\cos (90^\circ -

Vedclass · Accepted Answer

$\cot 	heta$

Vedclass · Answer

(B) In trigonometry,the trigonometric ratios of complementary angles are defined as follows:$\sin (90^\circ - 	heta) = \cos 	heta$$\cos (90^\circ - 	heta) = \sin 	heta$$	an (90^\circ - 	heta) = \cot 	heta$$\cot (90^\circ - 	heta) = 	an 	heta$$\sec (90^\circ - 	heta) = \operatorname{cosec} 	heta$$\operatorname{cosec} (90^\circ - 	heta) = \sec 	heta$Therefore,$	an (90^\circ - 	heta) = \cot 	heta$.

$\tan (90^\circ - \theta) = \ldots \ldots \ldots$

Similar Questions

If $1+\sin ^{2} \theta=3 \sin \theta \cos \theta,$ then prove that $\tan \theta=1$ or $\frac{1}{2}$.

$\cos 35^{\circ} = \ldots \ldots \ldots$

In $\Delta ABC$,$m \angle B = 90^{\circ}$,$BC = 3$ and $AC = 5$,then $\tan A = \ldots$

If $\operatorname{cosec} A = \sqrt{10}$,then $\sin A = \dots$

In $\Delta ABC$,$m\angle A = 90^\circ$,$AB = 5$,$AC = 12$ and $BC = 13$. Therefore,$\sin C + \cos C = \ldots$

Vedclass Test Series

Exam Paper Generator

Online Exam Module