In Delta ABC,angle B is a right angle. If AB | vedclass

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(B) In a right-angled triangle,the hypotenuse $AC$ can be calculated using the Pythagorean theorem: $AC = \sqrt{AB^2 + BC^2} = \sqrt{8^2 + 6^2} = \sqr

Vedclass · Accepted Answer

$2$

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(B) In a right-angled triangle,the hypotenuse $AC$ can be calculated using the Pythagorean theorem: $AC = \sqrt{AB^2 + BC^2} = \sqrt{8^2 + 6^2} = \sqrt{64 + 36} = \sqrt{100} = 10$.The radius $r$ of the incircle of a right-angled triangle is given by the formula $r = \frac{AB + BC - AC}{2}$.Substituting the values: $r = \frac{8 + 6 - 10}{2} = \frac{14 - 10}{2} = \frac{4}{2} = 2$.Therefore,the radius of the circle is $2$.

In $\Delta ABC$,$\angle B$ is a right angle. If $AB = 8$ and $BC = 6$,find the radius of the incircle of $\Delta ABC$.

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