A - M - B and if frac{AM}{AB} = frac{3}{5},th | vedclass

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(C) Given that $A - M - B$,the point $M$ lies on the line segment $AB$.We are given the ratio $\frac{AM}{AB} = \frac{3}{5}$.Since $AB = AM + MB$,we ca

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$3:2$

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(C) Given that $A - M - B$,the point $M$ lies on the line segment $AB$.We are given the ratio $\frac{AM}{AB} = \frac{3}{5}$.Since $AB = AM + MB$,we can substitute this into the equation:$\frac{AM}{AM + MB} = \frac{3}{5}$.By cross-multiplying or comparing the parts,we get $5(AM) = 3(AM + MB)$.$5(AM) = 3(AM) + 3(MB)$.$2(AM) = 3(MB)$.Therefore,$\frac{AM}{MB} = \frac{3}{2}$.Thus,the point $M$ divides the segment $AB$ in the ratio $3:2$ internally.

$A - M - B$ and if $\frac{AM}{AB} = \frac{3}{5}$,then $M$ divides $\overline{AB}$ from $A$ in the internal division ratio......

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