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(B) The perimeter of $\Delta ABC = AB + BC + AC = 4 + 8 + 10 = 22$.Since $\Delta ABC \sim \Delta PQR$,the ratio of their perimeters is equal to the ra

Vedclass · Accepted Answer

$33$

Vedclass · Answer

(B) The perimeter of $\Delta ABC = AB + BC + AC = 4 + 8 + 10 = 22$.Since $\Delta ABC \sim \Delta PQR$,the ratio of their perimeters is equal to the ratio of their corresponding sides.Therefore,$\frac{	ext{Perimeter of } \Delta ABC}{	ext{Perimeter of } \Delta PQR} = \frac{AC}{PR}$.Substituting the given values: $\frac{22}{	ext{Perimeter of } \Delta PQR} = \frac{10}{15}$.Simplifying the fraction: $\frac{22}{	ext{Perimeter of } \Delta PQR} = \frac{2}{3}$.Thus,the perimeter of $\Delta PQR = \frac{22 	imes 3}{2} = 11 	imes 3 = 33$.

$\Delta ABC \sim \Delta PQR$ for the correspondence $ABC \leftrightarrow PQR$. If $AB = 4, BC = 8, AC = 10$ and $PR = 15$,then the perimeter of $\Delta PQR = \dots$

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