If $\sin \theta = \frac{3}{5}$,then $\tan \theta = \ldots$

  • A
    $\frac{4}{3}$
  • B
    $\frac{5}{4}$
  • C
    $\frac{4}{5}$
  • D
    $\frac{3}{4}$

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Similar Questions

If $\tan \theta + \sec \theta = l$,then prove that $\sec \theta = \frac{l^{2} + 1}{2l}$.

$\sin \theta \cdot \cos (90^\circ - \theta) = \ldots \ldots \ldots$

$\frac{\cos 50^{\circ}}{\sin 40^{\circ}} + \frac{\sin 15^{\circ}}{\cos 75^{\circ}} = \ldots \ldots \ldots \ldots$

$\sec (90^\circ - \theta) = \dots$

In $\Delta ABC$,$m \angle C = 90^{\circ}$ and $\tan A = \frac{1}{\sqrt{3}}$,then $\sin A = \ldots$

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