frac{1}{sin ^{2} theta}-1 = ldots ldots ldots | vedclass

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Question

(B) We know that $\frac{1}{\sin 	heta} = \operatorname{cosec} 	heta$. Therefore,$\frac{1}{\sin ^{2} 	heta} = \operatorname{cosec}^{2} 	heta$. Subs

Vedclass · Accepted Answer

$\cot ^{2} 	heta$

Vedclass · Answer

(B) We know that $\frac{1}{\sin 	heta} = \operatorname{cosec} 	heta$. Therefore,$\frac{1}{\sin ^{2} 	heta} = \operatorname{cosec}^{2} 	heta$. Substituting this into the expression: $\operatorname{cosec}^{2} 	heta - 1$. Using the trigonometric identity $1 + \cot^{2} 	heta = \operatorname{cosec}^{2} 	heta$,we get $\operatorname{cosec}^{2} 	heta - 1 = \cot^{2} 	heta$.

$\frac{1}{\sin ^{2} \theta}-1 = \ldots \ldots \ldots$

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