The chemical reaction is shown below:C_6H_5-C | vedclass

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(C) The reaction follows Markovnikov's addition of $HCl$ to the alkene.$1$. The $H^+$ ion attacks the terminal carbon of the double bond to form the m

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(C) The reaction follows Markovnikov's addition of $HCl$ to the alkene.$1$. The $H^+$ ion attacks the terminal carbon of the double bond to form the most stable carbocation.$2$. The intermediate formed is a $3^{\circ}$ benzylic carbocation $(C_6H_5-CH^+-CH_2-CH_3)$,which is highly stabilized by resonance with the phenyl ring.$3$. The $Cl^-$ ion then attacks this carbocation to form the final product: $1$-chloro-$1$-phenylpropane $(C_6H_5-CH(Cl)-CH_2-CH_3)$.

The chemical reaction is shown below:
$C_6H_5-CH_2-CH=CH_2 + HCl \rightarrow X$,$X$ is:

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The chemical reaction is shown below:$C_6H_5-CH_2-CH=CH_2 + HCl \rightarrow X$,$X$ is: