C_{7}H_{10}O reacts with CH_{3}MgBr to give a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction of an aldehyde or ketone with $CH_{3}MgBr$ (Grignard reagent) followed by hydrolysis yields an alcohol.For the resulting alcohol to g

Vedclass · Accepted Answer

Vedclass · Answer

(C) The reaction of an aldehyde or ketone with $CH_{3}MgBr$ (Grignard reagent) followed by hydrolysis yields an alcohol.For the resulting alcohol to give a positive iodoform test,it must contain a $CH_{3}CH(OH)-$ group.Starting with $C_{7}H_{10}O$,if $A$ is cyclohex$-3-$ene$-1-$carbaldehyde,the reaction is:$C_{6}H_{9}CHO + CH_{3}MgBr \rightarrow C_{6}H_{9}CH(OMgBr)CH_{3}$Upon hydrolysis,this gives $C_{6}H_{9}CH(OH)CH_{3}$,which is a secondary alcohol with a $CH_{3}CH(OH)-$ group.This structure gives a positive iodoform test with $I_{2}/NaOH$.Thus,the structure of $A$ is cyclohex$-3-$ene$-1-$carbaldehyde.

$C_{7}H_{10}O$ reacts with $CH_{3}MgBr$ to give a compound $C_{8}H_{12}O$ which gives a positive iodoform test. Identify the structure of $A$.

Similar Questions

The major product formed in the following reaction is:

Identify the final product $D$ in the given reaction sequence:
$CH_3CH_2Cl$ $\xrightarrow{Aq. KOH} A$ $\xrightarrow{PCC} B$ $\xrightarrow{Cl_2/NaOH} C$ $\xrightarrow{Acetone} D$
Product $D$ is known as:

Which of the following reagents can form a hydrazone with alkanone?

Which among the following is a possible product during cross aldol condensation between propanal (as electrophile) and butanal (as nucleophile)?

The major aromatic product $C$ in the following reaction sequence will be :

Vedclass Test Series

Exam Paper Generator

Online Exam Module