A uniform rod of mass M and length L is place | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to the law of conservation of linear momentum,the total momentum of the system before the collision must equal the total momentum after

Vedclass · Accepted Answer

$mv/M$

Vedclass · Answer

(B) According to the law of conservation of linear momentum,the total momentum of the system before the collision must equal the total momentum after the collision.Before the collision,the momentum of the system is $P_i = mv + M(0) = mv$.After the collision,the particle comes to rest,so its momentum is $0$. Let the velocity of the centre of mass of the rod be $V_{cm}$. The momentum of the rod is $M V_{cm}$.Thus,$P_f = 0 + M V_{cm} = M V_{cm}$.Equating initial and final momentum: $mv = M V_{cm}$.Solving for $V_{cm}$,we get $V_{cm} = \frac{mv}{M}$.

Similar Questions

$A$ mass $m$ moving horizontally (along the $x-$ axis) with velocity $v$ collides and sticks to a mass of $3m$ moving vertically upward (along the $y-$ axis) with velocity $2v$. The final velocity of the combination is

$A$ current $I$ flows in an infinitely long wire with a cross-section in the form of a semicircular ring of radius $R$. The magnitude of the magnetic induction along its axis is

Chloramphenicol and erythromycin (broad spectrum antibiotics) are produced by

If the line $lx + my = 1$ is a normal to the hyperbola $\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1$,then $\frac{a^2}{l^2} - \frac{b^2}{m^2}$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module