(A) The reaction of $Cu_2Cl_2$ (cuprous chloride) with $HCl$ in the presence of an oxidizing agent (represented as $[O]$) leads to the oxidation of $C

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(A) The reaction of $Cu_2Cl_2$ (cuprous chloride) with $HCl$ in the presence of an oxidizing agent (represented as $[O]$) leads to the oxidation of $Cu(I)$ to $Cu(II)$.The balanced chemical equation is:$2CuCl + 2HCl + [O] \to 2CuCl_2 + H_2O$Thus,the product formed is $CuCl_2$.