K_2Cr_2O_7 on heating with aqueous NaOH gives | vedclass

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Question

(A) When potassium dichromate $(K_2Cr_2O_7)$ reacts with an aqueous solution of sodium hydroxide $(NaOH)$,it forms potassium chromate and sodium chrom

Vedclass · Accepted Answer

$CrO_4^{2-}$

Vedclass · Answer

(A) When potassium dichromate $(K_2Cr_2O_7)$ reacts with an aqueous solution of sodium hydroxide $(NaOH)$,it forms potassium chromate and sodium chromate.The chemical equation is: $K_2Cr_2O_7 + 2NaOH \rightarrow K_2CrO_4 + Na_2CrO_4 + H_2O$.In this reaction,the orange dichromate ion $(Cr_2O_7^{2-})$ is converted into the yellow chromate ion $(CrO_4^{2-})$.

$K_2Cr_2O_7$ on heating with aqueous $NaOH$ gives:

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Assertion : Solution of $Na_2CrO_4$ in water is intensely coloured.
Reason : Oxidation state of $Cr$ in $Na_2CrO_4$ is $+VI$.

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