1.86 g of aniline completely reacts to form | vedclass

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(B) The molar mass of aniline $(C_6H_5NH_2)$ is $93 \ g/mol$ and the molar mass of acetanilide $(C_6H_5NHCOCH_3)$ is $135 \ g/mol$.Reaction: $C_6H_5NH

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$243$

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(B) The molar mass of aniline $(C_6H_5NH_2)$ is $93 \ g/mol$ and the molar mass of acetanilide $(C_6H_5NHCOCH_3)$ is $135 \ g/mol$.Reaction: $C_6H_5NH_2 + CH_3COCl ightarrow C_6H_5NHCOCH_3 + HCl$.$1 \ mol$ of aniline produces $1 \ mol$ of acetanilide.Moles of aniline used $= \frac{1.86 \ g}{93 \ g/mol} = 0.02 \ mol$.Theoretical yield of acetanilide $= 0.02 \ mol 	imes 135 \ g/mol = 2.70 \ g$.Since $10 \ \%$ of the product is lost during purification,the yield is $90 \ \%$ of the theoretical yield.Actual yield $= 2.70 \ g 	imes 0.90 = 2.43 \ g$.$2.43 \ g = 243 	imes 10^{-2} \ g$.

$1.86 \ g$ of aniline completely reacts to form acetanilide. $10 \ \%$ of the product is lost during purification. Amount of acetanilide obtained after purification (in $g$) is ...... $\times 10^{-2}$.

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