The geometry of [Pt(NH_3)_4]Cl_2 is: | vedclass

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(A) In the complex $[Pt(NH_3)_4]Cl_2$,the central metal ion is $Pt^{2+}$.$Pt$ $(Z=78)$ has an electronic configuration of $[Xe] 4f^{14} 5d^9 6s^1$. Fo

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Square planar

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(A) In the complex $[Pt(NH_3)_4]Cl_2$,the central metal ion is $Pt^{2+}$.$Pt$ $(Z=78)$ has an electronic configuration of $[Xe] 4f^{14} 5d^9 6s^1$. For $Pt^{2+}$,the configuration is $[Xe] 4f^{14} 5d^8$.Since $NH_3$ is a strong field ligand,it causes pairing of electrons in the $5d$ orbitals.The four $NH_3$ ligands donate electron pairs to the empty $5d$,$6s$,and $6p$ orbitals,resulting in $dsp^2$ hybridisation.$A$ $dsp^2$ hybridised complex always exhibits a square planar geometry.

The geometry of $[Pt(NH_3)_4]Cl_2$ is:

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