$A + CCl_4 + KOH \to$ Salicylic acid
'$A$' in the above reaction is
'$A$' in the above reaction is
- APhenol
- BNitrobenzene
- CBenzene
- DBenzaldehyde
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The ionisation constant of phenol is higher than that of ethanol because
Medium
View SolutionThe major product of the following reaction sequence is:
Aniline $\xrightarrow[(i) NaNO_2, HCl, 273-278K]{(ii) H_2O, warm} \text{Product}$ $\xrightarrow[(iv) NaOH]{(iii) Br_2, (excess)} \text{Product}$ $\xrightarrow{(v) CH_3I} \text{Final Product}$
Aniline $\xrightarrow[(i) NaNO_2, HCl, 273-278K]{(ii) H_2O, warm} \text{Product}$ $\xrightarrow[(iv) NaOH]{(iii) Br_2, (excess)} \text{Product}$ $\xrightarrow{(v) CH_3I} \text{Final Product}$
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View SolutionPhenol with Hinsberg's reagent gives
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View SolutionThe increasing order of boiling points of the following compounds is:
Which of the following is a trihydric phenol?
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