C_2H_5CHO and (CH_3)_2CO can be distinguished | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The correct answer is $C$.
$C_2H_5CHO$ is an aldehyde,while $(CH_3)_2CO$ is a ketone.
Aldehydes reduce Fehling solution to give a red precipitat

Vedclass · Accepted Answer

Fehling solution

Vedclass · Answer

(C) The correct answer is $C$.
$C_2H_5CHO$ is an aldehyde,while $(CH_3)_2CO$ is a ketone.
Aldehydes reduce Fehling solution to give a red precipitate of cuprous oxide $(Cu_2O)$,whereas ketones do not react with Fehling solution.
The reaction for the aldehyde is: $C_2H_5CHO + 2Cu^{+2} + 5OH^{-} 	o C_2H_5COO^{-} + Cu_2O (	ext{red ppt}) + 3H_2O$.
Ketones like $(CH_3)_2CO$ do not show this reaction.

$C_2H_5CHO$ and $(CH_3)_2CO$ can be distinguished by testing with

Similar Questions

$C_6H_5CHO + C_6H_5COCH_3 \xrightarrow[293 \ K]{OH^{-}}$ product of reaction is . . . . . . .

Clemmensen reduction involves the conversion of $ >C=O $ to $ >CH_2 $ in the presence of:

Which product is formed when the compound $C_6H_5CHO$ is treated with concentrated $KOH$ solution?

Which of the following will give a yellow precipitate with $I_2/NaOH$?

Splitting of signals in $NMR$ spectroscopy is caused by

Vedclass Test Series

Exam Paper Generator

Online Exam Module