CH_3-CHO + CH_3-MgBr rightarrow text{Product} | vedclass

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Question

(B) Acetaldehyde $(CH_3-CHO)$ reacts with methylmagnesium bromide $(CH_3-MgBr)$ to form an addition product,which upon hydrolysis yields propan-$2$-ol

Vedclass · Accepted Answer

Secondary alcohol

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(B) Acetaldehyde $(CH_3-CHO)$ reacts with methylmagnesium bromide $(CH_3-MgBr)$ to form an addition product,which upon hydrolysis yields propan-$2$-ol $(CH_3-CH(OH)-CH_3)$.Since the $-OH$ group is attached to a carbon atom which is further attached to two other carbon atoms,it is a secondary alcohol.The reaction is: $CH_3-CHO + CH_3-MgBr$ $\rightarrow CH_3-CH(OMgBr)-CH_3$ $\xrightarrow{H_2O} CH_3-CH(OH)-CH_3 + Mg(OH)Br$.

$CH_3-CHO + CH_3-MgBr$ $\rightarrow \text{Product}$ $\xrightarrow{H_2O} A$. What is $A$?

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