lim _{x rightarrow 0} frac{sin ^{2}left(pi co | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) આપણે $L = \lim _{x \rightarrow 0} \frac{\sin ^{2}\left(\pi \cos ^{4} x\right)}{x^{4}}$ ની કિંમત મેળવવાની છે.જેમ $x \rightarrow 0$ થાય,તેમ $\cos x

Vedclass · Accepted Answer

$4 \pi^{2}$

Vedclass · Answer

(C) આપણે $L = \lim _{x ightarrow 0} \frac{\sin ^{2}\left(\pi \cos ^{4} xight)}{x^{4}}$ ની કિંમત મેળવવાની છે.જેમ $x ightarrow 0$ થાય,તેમ $\cos x ightarrow 1$ થાય,તેથી $\pi \cos^4 x ightarrow \pi$.ધારો કે $u = \pi \cos^4 x$. તો $\sin^2(u) = \sin^2(\pi - u) = \sin^2(\pi(1 - \cos^4 x))$.$x ightarrow 0$ માટે,$1 - \cos^4 x = \sin^2 x (1 + \cos^2 x)$.તેથી,$L = \lim _{x ightarrow 0} \frac{\sin^2(\pi \sin^2 x (1 + \cos^2 x))}{x^4}$.$\lim_{	heta ightarrow 0} \frac{\sin 	heta}{	heta} = 1$ નો ઉપયોગ કરતા:$L = \pi^2 \cdot \lim_{x}$ ${ightarrow 0} \left( \frac{\sin x}{x} ight)^4 \cdot (1 + \cos^2 x)^2 = \pi^2 \cdot 1^4 \cdot (1 + 1)^2 = 4 \pi^2$.

$\lim _{x \rightarrow 0} \frac{\sin ^{2}\left(\pi \cos ^{4} x\right)}{x^{4}}$ ની કિંમત શોધો.

Similar Questions

$\lim _{x \rightarrow 0} \frac{\sin \left(\pi \cos ^2 x\right)}{x^2}$ ની કિંમત શોધો.

$\mathop {\lim }\limits_{x \to 0} \frac{{\sin {x^\circ}}}{x} = $

$\mathop {\lim }\limits_{x \to 0} \frac{{1 - \cos 2x}}{x} = $

$\mathop {\lim }\limits_{x \to 0} \frac{{3\sin x - \sin 3x}}{{{x^3}}} = $

$\lim _{x \rightarrow \frac{\pi}{2}} \frac{1+\cos 2 x}{\cot 3 x\left(3^{\sin 2 x}-1\right)}=$

Vedclass Test Series

Exam Paper Generator

Online Exam Module