CO_{2} gas adsorbs on charcoal following Freu | vedclass

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(C) The Freundlich adsorption isotherm is given by the equation: $\frac{x}{m} = k \cdot p^{\frac{1}{n}}$.Let the initial mass adsorbed be $y_1 = \frac

Vedclass · Accepted Answer

$17$

Vedclass · Answer

(C) The Freundlich adsorption isotherm is given by the equation: $\frac{x}{m} = k \cdot p^{\frac{1}{n}}$.Let the initial mass adsorbed be $y_1 = \frac{x}{m} = k \cdot p^{\frac{1}{n}}$.When the pressure is doubled $(p' = 2p)$,the mass adsorbed becomes $y_2 = 64y_1 = k \cdot (2p)^{\frac{1}{n}}$.Dividing the two equations: $\frac{64y_1}{y_1} = \frac{k \cdot (2p)^{\frac{1}{n}}}{k \cdot p^{\frac{1}{n}}}$.$64 = (2)^{\frac{1}{n}}$.Since $64 = 2^6$,we have $2^6 = 2^{\frac{1}{n}}$.Therefore,$\frac{1}{n} = 6$,which implies $n = \frac{1}{6} \approx 0.1666$.Expressing this as $n 	imes 10^{-2}$,we get $16.66 	imes 10^{-2}$.Rounding to the nearest integer,we get $17 	imes 10^{-2}$.

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