Al_{2}O_{3(s)} + 2NaOH_{(aq)} xrightarrow{Del | vedclass

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Question

(C) Aluminum oxide $(Al_{2}O_{3})$ is an amphoteric oxide,meaning it reacts with both acids and bases.When $Al_{2}O_{3}$ reacts with a strong base lik

Vedclass · Accepted Answer

$2NaAlO_{2}$

Vedclass · Answer

(C) Aluminum oxide $(Al_{2}O_{3})$ is an amphoteric oxide,meaning it reacts with both acids and bases.When $Al_{2}O_{3}$ reacts with a strong base like sodium hydroxide $(NaOH)$,it forms sodium aluminate $(NaAlO_{2})$ and water.The balanced chemical equation for this reaction is:$Al_{2}O_{3(s)} + 2NaOH_{(aq)} \xrightarrow{\Delta} 2NaAlO_{2(aq)} + H_{2}O_{(l)}$Therefore,the missing product is $2NaAlO_{2}$.

$Al_{2}O_{3(s)} + 2NaOH_{(aq)} \xrightarrow{\Delta} \dots + H_{2}O_{(l)}$

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