$4-$methylbenzene sulphonic acid reacts with sodium acetate to give:

Identify the product $Y$ in the following reaction sequence:
$Benzene + CH_3CH_2CH_2Cl$ $\xrightarrow{AlCl_3} X$ $\xrightarrow{KMnO_4} Y$

Draw the structures of the following compounds:
$(i)$ $3-$Methylbutanal
$(ii)$ $p-$Nitropropiophenone
$(iii)$ $p-$Methylbenzaldehyde
$(iv)$ $4-$Methylpent$-3-$en$-2-$one
$(v)$ $4-$Chloropentan$-2-$one
$(vi)$ $3-$Bromo$-4-$phenylpentanoic acid
$(vii)$ $p, p^{\prime}-$Dihydroxybenzophenone
$(viii)$ Hex$-2-$en$-4-$ynoic acid

Which of the following compounds on hydrolysis gives reactant $(A)$?

Assertion : The $pK_a$ of acetic acid is lower than that of phenol.
Reason : Phenoxide ion is more resonance stabilised.

Find the correct match for the acid given in Column-$I$ with its formula in Column-$II$ and its $IUPAC$ name in Column-$III$.

Column-$I$ (Acid)	Column-$II$ (Formula) and Column-$III$ ($IUPAC$ Name)
$(A)$ Adipic acid	$(ii)$ $HOOC(CH_2)_4COOH$ ; $(y)$ Hexanedioic acid
$(B)$ Carballylic acid	$(iii)$ $HOOC-CH_2-CH(COOH)-CH_2-COOH$ ; $(n)$ Propane-$1,2,3$-tricarboxylic acid
$(C)$ Phthalic acid	$(i)$ $1,2-C_6H_4(COOH)_2$ ; $(x)$ Benzene-$1,2$-dicarboxylic acid
$(D)$ Glutaric acid	$(iv)$ $HOOC(CH_2)_3COOH$ ; $(m)$ Pentanedioic acid