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(D) Given mass of organic compound $= 120 \ g$. Mass of $CO_{2} = 330 \ g$. Mass of $H_{2}O = 270 \ g$. Mass of carbon $= (	ext{moles of } CO_{2})

Vedclass · Accepted Answer

$75$ and $25$

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(D) Given mass of organic compound $= 120 \ g$. Mass of $CO_{2} = 330 \ g$. Mass of $H_{2}O = 270 \ g$. Mass of carbon $= (	ext{moles of } CO_{2}) 	imes 12 = (330 / 44) 	imes 12 = 7.5 	imes 12 = 90 \ g$. Percentage of carbon $= (90 / 120) 	imes 100 = 75 \ \%$. Mass of hydrogen $= (	ext{moles of } H_{2}O) 	imes 2 = (270 / 18) 	imes 2 = 15 	imes 2 = 30 \ g$. Percentage of hydrogen $= (30 / 120) 	imes 100 = 25 \ \%$. Therefore,the percentages are $75 \ \%$ and $25 \ \%$ respectively.

$120 \ g$ of an organic compound that contains only carbon and hydrogen gives $330 \ g$ of $CO_{2}$ and $270 \ g$ of water on complete combustion. The percentage of carbon and hydrogen,respectively,are ...... .

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