2 , g of a non-volatile non-electrolyte solut | vedclass

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(A) The elevation in boiling point is given by the formula $\Delta T_b = K_b \cdot m$,where $K_b$ is the ebullioscopic constant and $m$ is the molalit

Vedclass · Accepted Answer

$8$

Vedclass · Answer

(A) The elevation in boiling point is given by the formula $\Delta T_b = K_b \cdot m$,where $K_b$ is the ebullioscopic constant and $m$ is the molality of the solution.Since the mass of the solute and the mass of the solvent are the same for both solutions,the molality $m$ is identical for both solvents $A$ and $B$.Given the ratio of ebullioscopic constants $\frac{(K_b)_A}{(K_b)_B} = \frac{1}{8}$.Therefore,the ratio of the elevation in boiling points is $\frac{(\Delta T_b)_A}{(\Delta T_b)_B} = \frac{(K_b)_A \cdot m}{(K_b)_B \cdot m} = \frac{(K_b)_A}{(K_b)_B} = \frac{1}{8}$.Comparing this to $\frac{x}{y}$,we get $x = 1$ and $y = 8$.The value of $y$ is $8$.

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