$Fe^{3+}$ cation gives a Prussian blue precipitate on addition of potassium ferrocyanide solution due to the formation of:
- A$[Fe(H_2O)_6]_2[Fe(CN)_6]$
- B$Fe_2[Fe(CN)_6]_2$
- C$Fe_3[Fe(OH)_2(CN)_4]_2$
- D$Fe_4[Fe(CN)_6]_3$
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Similar Questions
Assign $A, B, C, D$ from the given type of reaction.
$K_4[Fe(CN)_6] + 2CuSO_4 \longrightarrow Cu_2[Fe(CN)_6] \downarrow + 2K_2SO_4$
$K_4[Fe(CN)_6] + 2CuSO_4 \longrightarrow Cu_2[Fe(CN)_6] \downarrow + 2K_2SO_4$
Medium
View SolutionMatch List-$I$ with List-$II$.
List-$I$ (Compound) List-$II$ (Colour) $A$. $Fe_4[Fe(CN)_6]_3 \cdot xH_2O$ $I$. Violet $B$. $[Fe(CN)_5NOS]^{4-}$ $II$. Blood Red $C$. $[Fe(SCN)]^{2+}$ $III$. Prussian Blue $D$. $(NH_4)_3PO_4 \cdot 12MoO_3$ $IV$. Yellow
Choose the correct answer from the options given below:
| List-$I$ (Compound) | List-$II$ (Colour) |
| $A$. $Fe_4[Fe(CN)_6]_3 \cdot xH_2O$ | $I$. Violet |
| $B$. $[Fe(CN)_5NOS]^{4-}$ | $II$. Blood Red |
| $C$. $[Fe(SCN)]^{2+}$ | $III$. Prussian Blue |
| $D$. $(NH_4)_3PO_4 \cdot 12MoO_3$ | $IV$. Yellow |
Choose the correct answer from the options given below:
Assign $A, B, C, D$ from the given type of reaction.
$NiCl_2 + 2dmg \xrightarrow{NH_4OH} Ni(dmg)_2 \downarrow$
$NiCl_2 + 2dmg \xrightarrow{NH_4OH} Ni(dmg)_2 \downarrow$
Medium
View SolutionThe colour of tetrammine copper$(II)$ sulphate is
Medium
View Solution$A$ metal complex absorbed orange light. The colour in which it appears is
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