K_{a} for butyric acid (C_{3}H_{7}COOH) is 2 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For a weak acid,the $pH$ is given by the formula: $pH = \frac{1}{2} (pK_{a} - \log C)$.Given $K_{a} = 2 	imes 10^{-5}$,so $pK_{a} = -\log(2 	ime

Vedclass · Accepted Answer

$27$

Vedclass · Answer

(C) For a weak acid,the $pH$ is given by the formula: $pH = \frac{1}{2} (pK_{a} - \log C)$.Given $K_{a} = 2 	imes 10^{-5}$,so $pK_{a} = -\log(2 	imes 10^{-5}) = 5 - \log 2 = 5 - 0.30 = 4.7$.Concentration $C = 0.2 \ M = 2 	imes 10^{-1} \ M$.$pH = \frac{1}{2} (4.7 - \log(2 	imes 10^{-1}))$.$pH = \frac{1}{2} (4.7 - (\log 2 + \log 10^{-1}))$.$pH = \frac{1}{2} (4.7 - (0.30 - 1)) = \frac{1}{2} (4.7 - (-0.7)) = \frac{1}{2} (5.4) = 2.7$.$pH = 2.7 = 27 	imes 10^{-1}$.Thus,the value is $27$.

$K_{a}$ for butyric acid $(C_{3}H_{7}COOH)$ is $2 \times 10^{-5}$. The $pH$ of $0.2 \ M$ solution of butyric acid is $........... \times 10^{-1}$. (Nearest integer) [Given $\log 2 = 0.30$]

Similar Questions

The degree of ionization of a $0.1 \, M$ bromoacetic acid solution is $0.132$. Calculate the $pH$ of the solution and the $pK_{a}$ of bromoacetic acid.

The amount of acetic acid in $1 \ L$ of solution having $\alpha = 1\%$ and $K_a = 1.8 \times 10^{-5}$ is ............. $g$.

The $pH$ of $0.01 \ M \ BOH$ solution is $10$. What is its degree of dissociation (in $\%$)? (Given $K_{b}$ of $BOH$ is $1 \times 10^{-6}$)

$A$ weak monoacidic base is $1.2 \%$ dissociated in its $0.2 \ M$ solution. What is the value of dissociation constant?

What is the $pH$ of a weak dibasic acid,that is $2 \%$ dissociated in its $M/100$ solution at $298 \ K$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module