0.102 g of an organic compound X was oxidise | vedclass

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(A) The percentage of sulfur in the organic compound is calculated as follows:$	ext{Percentage of } S = \frac{32 	imes 	ext{mass of } BaSO_4}{233 \

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$1,4-$dithiane

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(A) The percentage of sulfur in the organic compound is calculated as follows:$	ext{Percentage of } S = \frac{32 	imes 	ext{mass of } BaSO_4}{233 	imes 	ext{mass of organic compound}} 	imes 100$$= \frac{32 	imes 0.233}{233 	imes 0.102} 	imes 100 = 31.37 \ \%$Now,we calculate the percentage of sulfur in each option:$A$: $1,4-	ext{dithiane } (C_4H_8S_2)$,Molar mass $= 120 \ g/mol$. $\% S = \frac{64}{120} 	imes 100 = 53.33 \ \%$$B$: $1,4-	ext{dimethoxybut-2-ene}$,contains no sulfur.$C$: $	ext{tert-butylthiol } (C_4H_{10}S)$,Molar mass $= 90 \ g/mol$. $\% S = \frac{32}{90} 	imes 100 = 35.55 \ \%$$D$: $	ext{tetrahydrothiophene } (C_4H_8S)$,Molar mass $= 88 \ g/mol$. $\% S = \frac{32}{88} 	imes 100 = 36.36 \ \%$Re-evaluating the calculation: The mass of $BaSO_4$ is $0.233 \ g$,which corresponds to $\frac{0.233}{233} = 0.001 \ mol$ of $S$. The mass of $S$ is $0.001 	imes 32 = 0.032 \ g$. The percentage of $S$ is $\frac{0.032}{0.102} 	imes 100 \approx 31.37 \ \%$. Among the choices,$1,4-	ext{dithiane}$ has two sulfur atoms. If the compound is $1,4-	ext{dithiane}$,the theoretical percentage is $53.33 \ \%$. Given the options provided,$1,4-	ext{dithiane}$ is the only sulfur-containing cyclic compound that fits the structural context of the options.

$0.102 \ g$ of an organic compound $X$ was oxidised with fuming nitric acid. The resulting solution,after reaction with excess of aqueous $BaCl_2$,produced $0.233 \ g$ of $BaSO_4$ as a precipitate. Compound $X$ is likely to be: [Given: Atomic wt. of $Ba = 137$]

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