CO_2 is passed through lime water. Initially, | vedclass

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Question

(D) The correct option is $D$.When $CO_2$ is passed through lime water $(Ca(OH)_2)$,it initially turns milky due to the formation of insoluble calcium

Vedclass · Accepted Answer

$Ca(HCO_3)_2$

Vedclass · Answer

(D) The correct option is $D$.When $CO_2$ is passed through lime water $(Ca(OH)_2)$,it initially turns milky due to the formation of insoluble calcium carbonate $(CaCO_3)$:$Ca(OH)_2 + CO_2 \rightarrow CaCO_3 \downarrow + H_2O$On continuous bubbling of $CO_2$,the milky precipitate dissolves to form soluble calcium bicarbonate $(Ca(HCO_3)_2)$,making the solution clear:$CaCO_3 + CO_2 + H_2O \rightarrow Ca(HCO_3)_2(aq)$

$CO_2$ is passed through lime water. Initially,the solution turns milky and then becomes clear upon continued bubbling of $CO_2$. The clear solution is due to the formation of:

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