(C) $1$. Calculate the moles of $CaCl_2$: $\text{moles} = \frac{222 \times 10^{-3} \ g}{111 \ g/mol} = 2 \times 10^{-3} \ mol$.$2$. Calculate the fina

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(C) $1$. Calculate the moles of $CaCl_2$: $\text{moles} = \frac{222 \times 10^{-3} \ g}{111 \ g/mol} = 2 \times 10^{-3} \ mol$.$2$. Calculate the final molarity of $CaCl_2$ after dilution to $100 \ mL$ $(0.1 \ L)$: $M = \frac{2 \times 10^{-3} \ mol}{0.1 \ L} = 0.02 \ M$.$3$. Dissociation of $CaCl_2$: $CaCl_2 \rightarrow Ca^{2+} + 2Cl^-$.$4$. Concentration of $Cl^-$ ions: $[Cl^-] = 2 \times [CaCl_2] = 2 \times 0.02 \ M = 0.04 \ mol/L$.

Class 11 Chemistry Some Basic Concepts of Chemistry Chemical stoichiometry

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$10 \ mL$ of an aqueous solution containing $222 \ mg$ of calcium chloride $(mol. wt. = 111)$ is diluted to $100 \ mL$. The concentration of chloride ion in the resulting solution is $..... \ mol/L$.

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A
$0.02$
B
$0.01$
C
$0.04$
D
$2.0$

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Some Basic Concepts of Chemistry

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Chemical stoichiometry

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$10 \ mL$ of an aqueous solution containing $222 \ mg$ of calcium chloride $(mol. wt. = 111)$ is diluted to $100 \ mL$. The concentration of chloride ion in the resulting solution is $..... \ mol/L$.

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