X-rays of wavelength 22 , pm are scattered fr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The Compton shift $\Delta \lambda$ is given by the formula: $\Delta \lambda = \frac{h}{m_0 c} (1 - \cos \phi)$.Here, the Compton wavelength $\lamb

Vedclass · Accepted Answer

$2.2$

Vedclass · Answer

(A) The Compton shift $\Delta \lambda$ is given by the formula: $\Delta \lambda = \frac{h}{m_0 c} (1 - \cos \phi)$.Here, the Compton wavelength $\lambda_c = \frac{h}{m_0 c} \approx 2.43 	imes 10^{-12} \, m = 2.43 \, pm$.The scattering angle $\phi = 85^{\circ}$.Substituting the values: $\Delta \lambda = 2.43 	imes (1 - \cos 85^{\circ})$.Since $\cos 85^{\circ} \approx 0.087$, we have $\Delta \lambda = 2.43 	imes (1 - 0.087) = 2.43 	imes 0.913 \approx 2.218 \, pm$.Rounding to the nearest given option, the Compton shift is approximately $2.2 \, pm$.

$X$-rays of wavelength $22 \, pm$ are scattered from a carbon target at an angle of $85^{\circ}$ to the incident beam. The Compton shift for $X$-rays is ......... $pm$.

Similar Questions

The continuous $X-$ray spectrum produced by an $X-$ray machine at constant voltage has

The wavelength of the most energetic $X$-rays emitted when a metal target is bombarded by $40 \ keV$ electrons is approximately .............. $\mathring{A}$.

When cathode rays strike a metal target with a high melting point and high atomic number,what is produced?

The figure represents the observed intensity of $X-$ rays emitted by an $X-$ ray tube as a function of wavelength. The sharp peaks $A$ and $B$ denote

For harder $X$-rays:

Vedclass Test Series

Exam Paper Generator

Online Exam Module