What is the distance between two consecutive | vedclass

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(D) In the $B-DNA$ double helix model proposed by Watson and Crick, the distance between two consecutive base pairs is $0.34 \, nm$ (or $3.4 \, \mathr

Vedclass · Accepted Answer

$0.34$

Vedclass · Answer

(D) In the $B-DNA$ double helix model proposed by Watson and Crick, the distance between two consecutive base pairs is $0.34 \, nm$ (or $3.4 \, \mathring{A}$). This distance is calculated by dividing the total pitch of one full turn of the helix $(3.4 \, nm)$ by the number of base pairs per turn $(10)$. Therefore, the distance between two adjacent base pairs is $0.34 \, nm$.

What is the distance between two consecutive base pairs in the structure of $DNA$ (in $nm$)?

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