K is the force constant of a spring. The work | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The potential energy stored in a spring with force constant $K$ at an extension $x$ is given by $U = \frac{1}{2}Kx^2$.At extension $l_1$,the store

Vedclass · Accepted Answer

$\frac{K}{2}(l_2^2 - l_1^2)$

Vedclass · Answer

(D) The potential energy stored in a spring with force constant $K$ at an extension $x$ is given by $U = \frac{1}{2}Kx^2$.At extension $l_1$,the stored potential energy is $U_1 = \frac{1}{2}Kl_1^2$.At extension $l_2$,the stored potential energy is $U_2 = \frac{1}{2}Kl_2^2$.The work done $W$ in increasing the extension from $l_1$ to $l_2$ is equal to the change in potential energy:$W = U_2 - U_1$$W = \frac{1}{2}Kl_2^2 - \frac{1}{2}Kl_1^2$$W = \frac{1}{2}K(l_2^2 - l_1^2)$.

$K$ is the force constant of a spring. The work done in increasing its extension from $l_1$ to $l_2$ will be

Similar Questions

Show that the law of conservation of mechanical energy is obeyed by pulling or compressing the block tied at the end of a spring.

Find the maximum tension in the spring if the spring is initially at its natural length when the block of mass $m$ is released from rest.

$A$ spring has a spring constant $200 \,N/m$. If it is stretched by $1 \,cm$, then the potential energy stored in it is: (in $\,J$)

Two springs have their force constants as $k_1$ and $k_2$ $(k_1 > k_2)$. When they are stretched by the same force,which of the following is true?

Is the work done by the stretching force in a stretched spring positive or negative?

Vedclass Test Series

Exam Paper Generator

Online Exam Module