The K_{H} values for some gases at the same t | vedclass

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(A) According to Henry's Law, the solubility of a gas in a liquid is inversely proportional to the Henry's Law constant $(K_{H})$.
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$Ar < CO_{2} < CH_{4} < HCHO$

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(A) According to Henry's Law, the solubility of a gas in a liquid is inversely proportional to the Henry's Law constant $(K_{H})$. Mathematically, $S \propto 1 / K_{H}$. Therefore, a higher value of $K_{H}$ indicates lower solubility, and a lower value of $K_{H}$ indicates higher solubility. Comparing the given $K_{H}$ values: $Ar (40.3) > CO_{2} (1.67) > CH_{4} (0.413) > HCHO (1.83 imes 10^{-5})$. Thus, the order of solubility in water is: $Ar < CO_{2} < CH_{4} < HCHO$.

Gas	$K_{H} / \text{kbar}$
$Ar$	$40.3$
$CO_{2}$	$1.67$
$HCHO$	$1.83 \times 10^{-5}$
$CH_{4}$	$0.413$

The $K_{H}$ values for some gases at the same temperature '$T$' are given below:

Gas $K_{H} / \text{kbar}$

$Ar$ $40.3$

$CO_{2}$ $1.67$

$HCHO$ $1.83 \times 10^{-5}$

$CH_{4}$ $0.413$

where $K_{H}$ is Henry's Law constant in water. The order of their solubility in water is:

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The $K_{H}$ values for some gases at the same temperature '$T$' are given below: Gas $K_{H} / \text{kbar}$ $Ar$ $40.3$ $CO_{2}$ $1.67$ $HCHO$ $1.83 \times 10^{-5}$ $CH_{4}$ $0.413$ where $K_{H}$ is Henry's Law constant in water. The order of their solubility in water is: