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(B) When borax $(Na_2B_4O_7 \cdot 10H_2O)$ is heated,it first loses its water of crystallization and then melts to form a transparent liquid which sol

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$B_2O_3$

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(B) When borax $(Na_2B_4O_7 \cdot 10H_2O)$ is heated,it first loses its water of crystallization and then melts to form a transparent liquid which solidifies into a glass-like mass consisting of sodium metaborate $(NaBO_2)$ and boric anhydride $(B_2O_3)$. The balanced chemical equation is: $Na_2B_4O_7 \stackrel{\Delta}{\longrightarrow} 2NaBO_2 + B_2O_3$ Thus,the product $X$ is $B_2O_3$.

$Na_2B_4O_7 \stackrel{\text{heat}}{\longrightarrow} X + NaBO_2$
In the above reaction,the product $X$ is:

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Borax is converted into crystalline boron by the following steps:
$Borax$ $\xrightarrow{X} H_3BO_3$ $\xrightarrow{\Delta} B_2O_3$ $\xrightarrow[\Delta]{Y} B$
$X$ and $Y$ are respectively:

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$Na_2B_4O_7 \stackrel{\text{heat}}{\longrightarrow} X + NaBO_2$ In the above reaction,the product $X$ is: