Be(OH)_2 reacts with Sr(OH)_2 to yield an ion | vedclass

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Question

(D) $Be(OH)_2$ is amphoteric in nature,while $Sr(OH)_2$ is basic in nature.These two undergo an acid-base neutralization reaction to form the salt $Sr

Vedclass · Accepted Answer

The element $Be$ is present in the cationic part of the ionic salt.

Vedclass · Answer

(D) $Be(OH)_2$ is amphoteric in nature,while $Sr(OH)_2$ is basic in nature.These two undergo an acid-base neutralization reaction to form the salt $Sr[Be(OH)_4]$.In this salt,$Sr^{2+}$ is the cation and $[Be(OH)_4]^{2-}$ is the complex anion.Therefore,$Be$ is present in the anionic part of the salt,not the cationic part.Thus,option $D$ is the incorrect statement.

$Be(OH)_2$ reacts with $Sr(OH)_2$ to yield an ionic salt. Choose the incorrect option related to this reaction from the following:

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