0.05 M CuSO_4 when treated with 0.01 M K_ | vedclass

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(D) Osmosis is the movement of solvent molecules from a region of lower solute concentration to a region of higher solute concentration through a Semi

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Molarity of $CuSO_4$ solution is lowered.

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(D) Osmosis is the movement of solvent molecules from a region of lower solute concentration to a region of higher solute concentration through a Semi Permeable Membrane $(SPM)$.Here,$0.01 \ M \ K_2Cr_2O_7$ (Side $X$) has a lower concentration than $0.05 \ M \ CuSO_4$ (Side $Y$).Therefore,solvent molecules move from Side $X$ to Side $Y$.As solvent moves to Side $Y$,the $CuSO_4$ solution becomes more dilute,and the $K_2Cr_2O_7$ solution becomes more concentrated.Since the solvent moves to Side $Y$,the $K_2Cr_2O_7$ molecules from Side $X$ cannot pass through the $SPM$ to react with $CuSO_4$ on Side $Y$. However,if we consider the net movement of solvent,the concentration of $CuSO_4$ on Side $Y$ decreases due to dilution.Thus,the molarity of the $CuSO_4$ solution is lowered.

$0.05 \ M \ CuSO_4$ when treated with $0.01 \ M \ K_2Cr_2O_7$ gives a green coloured solution of $Cu_2Cr_2O_7$. In an osmosis setup with a Semi Permeable Membrane $(SPM)$ separating Side $X$ $(K_2Cr_2O_7)$ and Side $Y$ $(CuSO_4)$,determine the observation due to osmosis.

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